Census puzzle

Mr. and Mrs. Jorkins have fifteen children, all born at intervals of one year and a half. Miss Ada Jorkins, the eldest, had an objection to state her age to the census man, but she admitted the she was just seven times older than little Johinne, the youngest of all. What was Ada's age ?

Do not too hastily assume that you have solved this little poser. You may find that you have made a bad blunder!

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1 Response to “Census puzzle”


  1. 1 S.Karthikeyan June 20, 2006 at 12:03 pm

    Ankur.

    Frankly I am confused. Here I quote the text from solution section. 😦

    Miss Ada Jorkins must have neen twenty four and her little brother Johnnie three years of age, with thirteen brothers and sisters between. There was a trap for the solver in the words “seven times older than little Johnnie”.

    Of course, “seven times older” is equal to eigth times as old. It is surprising how many people hastily assumes that it is same as “seven times as old”

    Probably many of you thought that the ages 24.5 and 3.5 were correct.

  2. 2 Ankur June 20, 2006 at 10:29 am

    jet johny’s age be x
    ada’s age = x + 14*1.5 or 7x

    6x = 14 * 1.5
    x = 3.5
    Hence Ada’s age is 24.5


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